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0.09x^2+0.06x-325=0
a = 0.09; b = 0.06; c = -325;
Δ = b2-4ac
Δ = 0.062-4·0.09·(-325)
Δ = 117.0036
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.06)-\sqrt{117.0036}}{2*0.09}=\frac{-0.06-\sqrt{117.0036}}{0.18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.06)+\sqrt{117.0036}}{2*0.09}=\frac{-0.06+\sqrt{117.0036}}{0.18} $
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